4x^2=7(4x-7)

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Solution for 4x^2=7(4x-7) equation: 



4x^2=7(4x-7)

We move all terms to the left:

4x^2-(7(4x-7))=0



We calculate terms in parentheses: -(7(4x-7)), so:

7(4x-7)

We multiply parentheses

28x-49

Back to the equation:

-(28x-49)



We get rid of parentheses

4x^2-28x+49=0

a = 4; b = -28; c = +49;
Δ = b2-4ac
Δ = -282-4·4·49
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{28}{8}=3+1/2$

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